What is the basic weight of 1 square foot of steel that is 1 inch thick?

The correct answer is 40.83 pounds, which represents the weight of 1 square foot of steel that is 1 inch thick. To derive this weight, you start by referring to the density of steel, which is approximately 490 pounds per cubic foot.

To find the weight of 1 square foot of steel at a thickness of 1 inch, first convert the thickness from inches to feet. Since there are 12 inches in a foot, 1 inch is equivalent to 1/12 of a foot.

Next, calculate the volume of the steel by multiplying the area (1 square foot) by the thickness (1/12 foot):

Volume = Area × Thickness Volume = 1 sq ft × (1/12) ft = 1/12 cubic feet

Now, using the density of steel to calculate the weight:

Weight = Volume × Density Weight = (1/12) cubic feet × 490 pounds per cubic foot = 40.83 pounds

This calculation shows that 1 square foot of steel at a thickness of 1 inch indeed weighs 40.83 pounds. Understanding this fundamental principle of weight density and volume relationships is crucial in rigging and heavy lifting applications, where precise weight calculations are